Base | Representation |
---|---|
bin | 1011111011110000000001… |
… | …1011100010111010111011 |
3 | 1201110100221021022110100212 |
4 | 2332330000123202322323 |
5 | 3204434034332411303 |
6 | 43523433122221335 |
7 | 2522653614266621 |
oct | 276740033427273 |
9 | 51410837273325 |
10 | 13121132310203 |
11 | 41a9706138275 |
12 | 157ab687b484b |
13 | 742418626b08 |
14 | 3350cd8bb511 |
15 | 17b49dc56ad8 |
hex | bef006e2ebb |
13121132310203 has 2 divisors, whose sum is σ = 13121132310204. Its totient is φ = 13121132310202.
The previous prime is 13121132310193. The next prime is 13121132310227. The reversal of 13121132310203 is 30201323112131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13121132310203 - 226 = 13121065201339 is a prime.
It is a super-2 number, since 2×131211323102032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13121132310703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560566155101 + 6560566155102.
It is an arithmetic number, because the mean of its divisors is an integer number (6560566155102).
Almost surely, 213121132310203 is an apocalyptic number.
13121132310203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121132310203 is an equidigital number, since it uses as much as digits as its factorization.
13121132310203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13121132310203 its reverse (30201323112131), we get a palindrome (43322455422334).
The spelling of 13121132310203 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty-two million, three hundred ten thousand, two hundred three".
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