131211434310042 has 16 divisors (see below), whose sum is σ = 263796810342912. Its totient is φ = 43508154482880.

The previous prime is 131211434310029. The next prime is 131211434310071. The reversal of 131211434310042 is 240013434112131.

It is a super-3 number, since 3×131211434310042³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131211434309991 and 131211434310009.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57247570543 + ... + 57247572834.

It is an arithmetic number, because the mean of its divisors is an integer number (16487300646432).

Almost surely, 2^{131211434310042} is an apocalyptic number.

131211434310042 is an abundant number, since it is smaller than the sum of its proper divisors (132585376032870).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131211434310042 is a wasteful number, since it uses less digits than its factorization.

131211434310042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114495143573.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 131211434310042 its reverse (240013434112131), we get a palindrome (371224868422173).

The spelling of 131211434310042 in words is "one hundred thirty-one trillion, two hundred eleven billion, four hundred thirty-four million, three hundred ten thousand, forty-two".