131212021433 has 2 divisors, whose sum is σ = 131212021434. Its totient is φ = 131212021432.

The previous prime is 131212021411. The next prime is 131212021441. The reversal of 131212021433 is 334120212131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113102398249 + 18109623184 = 336307^2 + 134572^2 .

It is an emirp because it is prime and its reverse (334120212131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131212021433 - 2²² = 131207827129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131212021399 and 131212021408.

It is not a weakly prime, because it can be changed into another prime (131212023433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606010716 + 65606010717.

It is an arithmetic number, because the mean of its divisors is an integer number (65606010717).

Almost surely, 2^131212021433 is an apocalyptic number.

It is an amenable number.

131212021433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212021433 is an equidigital number, since it uses as much as digits as its factorization.

131212021433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 131212021433 its reverse (334120212131), we get a palindrome (465332233564).

The spelling of 131212021433 in words is "one hundred thirty-one billion, two hundred twelve million, twenty-one thousand, four hundred thirty-three".