Base | Representation |
---|---|
bin | 111101000110011011… |
… | …0100011101010111100 |
3 | 110112200101202212202201 |
4 | 1322030312203222330 |
5 | 4122210301143004 |
6 | 140140015201244 |
7 | 12323362465663 |
oct | 1721466435274 |
9 | 415611685681 |
10 | 131212131004 |
11 | 50712911099 |
12 | 2151a816224 |
13 | c4b1055806 |
14 | 64ca475dda |
15 | 362e4986a4 |
hex | 1e8cda3abc |
131212131004 has 6 divisors (see below), whose sum is σ = 229621229264. Its totient is φ = 65606065500.
The previous prime is 131212130971. The next prime is 131212131031. The reversal of 131212131004 is 400131212131.
It is a super-2 number, since 2×1312121310042 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16401516372 + ... + 16401516379.
Almost surely, 2131212131004 is an apocalyptic number.
It is an amenable number.
131212131004 is a deficient number, since it is larger than the sum of its proper divisors (98409098260).
131212131004 is a wasteful number, since it uses less digits than its factorization.
131212131004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32803032755 (or 32803032753 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 131212131004 its reverse (400131212131), we get a palindrome (531343343135).
The spelling of 131212131004 in words is "one hundred thirty-one billion, two hundred twelve million, one hundred thirty-one thousand, four".
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