Base | Representation |
---|---|
bin | 11101110101011000111001… |
… | …010110001001011101000001 |
3 | 122012120202122201122002011122 |
4 | 131311120321112021131001 |
5 | 114144240103012000001 |
6 | 1143022020345322025 |
7 | 36431524646201510 |
oct | 3565307126113501 |
9 | 565522581562148 |
10 | 131212213000001 |
11 | 388988725a7a51 |
12 | 12871980796315 |
13 | 582a349190bc3 |
14 | 24589c270c677 |
15 | 10281e657ab1b |
hex | 775639589741 |
131212213000001 has 32 divisors (see below), whose sum is σ = 156784704565248. Its totient is φ = 107366012550720.
The previous prime is 131212212999991. The next prime is 131212213000019. The reversal of 131212213000001 is 100000312212131.
It is not a de Polignac number, because 131212213000001 - 218 = 131212212737857 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131212213008001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 531033356 + ... + 531280386.
It is an arithmetic number, because the mean of its divisors is an integer number (4899522017664).
Almost surely, 2131212213000001 is an apocalyptic number.
It is an amenable number.
131212213000001 is a deficient number, since it is larger than the sum of its proper divisors (25572491565247).
131212213000001 is a wasteful number, since it uses less digits than its factorization.
131212213000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 253541.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 131212213000001 its reverse (100000312212131), we get a palindrome (231212525212132).
The spelling of 131212213000001 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred thirteen million, one", and thus it is an aban number.
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