Base | Representation |
---|---|
bin | 11101110101011000111001… |
… | …010110001011011010000001 |
3 | 122012120202122201122111010221 |
4 | 131311120321112023122001 |
5 | 114144240103012224001 |
6 | 1143022020345423041 |
7 | 36431524646234026 |
oct | 3565307126133201 |
9 | 565522581574127 |
10 | 131212213008001 |
11 | 38898872602a64 |
12 | 1287198079aa81 |
13 | 582a349194738 |
14 | 24589c271154d |
15 | 10281e657d1a1 |
hex | 77563958b681 |
131212213008001 has 2 divisors, whose sum is σ = 131212213008002. Its totient is φ = 131212213008000.
The previous prime is 131212213007971. The next prime is 131212213008059. The reversal of 131212213008001 is 100800312212131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130523221704976 + 688991303025 = 11424676^2 + 830055^2 .
It is a cyclic number.
It is not a de Polignac number, because 131212213008001 - 241 = 129013189752449 is a prime.
It is not a weakly prime, because it can be changed into another prime (131212213008061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606106504000 + 65606106504001.
It is an arithmetic number, because the mean of its divisors is an integer number (65606106504001).
Almost surely, 2131212213008001 is an apocalyptic number.
It is an amenable number.
131212213008001 is a deficient number, since it is larger than the sum of its proper divisors (1).
131212213008001 is an equidigital number, since it uses as much as digits as its factorization.
131212213008001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
The spelling of 131212213008001 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred thirteen million, eight thousand, one".
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