1312123012333 has 4 divisors (see below), whose sum is σ = 1499569156960. Its totient is φ = 1124676867708.

The previous prime is 1312123012303. The next prime is 1312123012349. The reversal of 1312123012333 is 3332103212131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312123012333 - 2⁵ = 1312123012301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312123012298 and 1312123012307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312123012303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93723072303 + ... + 93723072316.

It is an arithmetic number, because the mean of its divisors is an integer number (374892289240).

Almost surely, 2^{1312123012333} is an apocalyptic number.

It is an amenable number.

1312123012333 is a deficient number, since it is larger than the sum of its proper divisors (187446144627).

1312123012333 is an equidigital number, since it uses as much as digits as its factorization.

1312123012333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 187446144626.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1312123012333 its reverse (3332103212131), we get a palindrome (4644226224464).

The spelling of 1312123012333 in words is "one trillion, three hundred twelve billion, one hundred twenty-three million, twelve thousand, three hundred thirty-three".