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13121231231123 is a prime number
BaseRepresentation
bin1011111011110000011001…
…0100111001100010010011
31201110101012011110011100122
42332330012110321202103
53204434240143343443
643523451014340455
72522656225146041
oct276740624714223
951411164404318
1013121231231123
1141a9756a61aa4
12157ab9595a72b
13742432c803c2
143350dcaab391
1517b4a7796968
hexbef06539893

13121231231123 has 2 divisors, whose sum is σ = 13121231231124. Its totient is φ = 13121231231122.

The previous prime is 13121231231083. The next prime is 13121231231159. The reversal of 13121231231123 is 32113213212131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13121231231123 - 214 = 13121231214739 is a prime.

It is a super-2 number, since 2×131212312311232 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13121231231092 and 13121231231101.

It is not a weakly prime, because it can be changed into another prime (13121231201123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560615615561 + 6560615615562.

It is an arithmetic number, because the mean of its divisors is an integer number (6560615615562).

Almost surely, 213121231231123 is an apocalyptic number.

13121231231123 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121231231123 is an equidigital number, since it uses as much as digits as its factorization.

13121231231123 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296, while the sum is 26.

Adding to 13121231231123 its reverse (32113213212131), we get a palindrome (45234444443254).

The spelling of 13121231231123 in words is "thirteen trillion, one hundred twenty-one billion, two hundred thirty-one million, two hundred thirty-one thousand, one hundred twenty-three".