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1312123909433 is a prime number
BaseRepresentation
bin10011000110000000101…
…011011111010100111001
311122102211011121212100212
4103012000223133110321
5132444212210100213
62442440441040505
7163540440131201
oct23060053372471
94572734555325
101312123909433
11466517815857
1219236b786135
139696ab2444c
144771581d401
15241e84be9a8
hex13180adf539

1312123909433 has 2 divisors, whose sum is σ = 1312123909434. Its totient is φ = 1312123909432.

The previous prime is 1312123909429. The next prime is 1312123909487. The reversal of 1312123909433 is 3349093212131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1308491195449 + 3632713984 = 1143893^2 + 60272^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312123909433 - 22 = 1312123909429 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312123909333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656061954716 + 656061954717.

It is an arithmetic number, because the mean of its divisors is an integer number (656061954717).

Almost surely, 21312123909433 is an apocalyptic number.

It is an amenable number.

1312123909433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312123909433 is an equidigital number, since it uses as much as digits as its factorization.

1312123909433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 104976, while the sum is 41.

The spelling of 1312123909433 in words is "one trillion, three hundred twelve billion, one hundred twenty-three million, nine hundred nine thousand, four hundred thirty-three".