1312127134537 has 2 divisors, whose sum is σ = 1312127134538. Its totient is φ = 1312127134536.

The previous prime is 1312127134429. The next prime is 1312127134541. The reversal of 1312127134537 is 7354317212131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 774451040841 + 537676093696 = 880029^2 + 733264^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312127134537 - 2¹¹ = 1312127132489 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1312127134537.

It is not a weakly prime, because it can be changed into another prime (1312127134597) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656063567268 + 656063567269.

It is an arithmetic number, because the mean of its divisors is an integer number (656063567269).

Almost surely, 2^{1312127134537} is an apocalyptic number.

It is an amenable number.

1312127134537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312127134537 is an equidigital number, since it uses as much as digits as its factorization.

1312127134537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 105840, while the sum is 40.

The spelling of 1312127134537 in words is "one trillion, three hundred twelve billion, one hundred twenty-seven million, one hundred thirty-four thousand, five hundred thirty-seven".