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1312132002169 is a prime number
BaseRepresentation
bin10011000110000001001…
…010010111000101111001
311122102211201212000111211
4103012001022113011321
5132444221243032134
62442441330323121
7163540565665162
oct23060112270571
94572751760454
101312132002169
11466521342a6a
121923724294a1
139696c6c8b51
1447716928769
15241e906c764
hex13181297179

1312132002169 has 2 divisors, whose sum is σ = 1312132002170. Its totient is φ = 1312132002168.

The previous prime is 1312132002079. The next prime is 1312132002331. The reversal of 1312132002169 is 9612002312131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1190531943225 + 121600058944 = 1091115^2 + 348712^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312132002169 - 221 = 1312129905017 is a prime.

It is a super-2 number, since 2×13121320021692 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1312132002169.

It is not a weakly prime, because it can be changed into another prime (1312132072169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656066001084 + 656066001085.

It is an arithmetic number, because the mean of its divisors is an integer number (656066001085).

Almost surely, 21312132002169 is an apocalyptic number.

It is an amenable number.

1312132002169 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312132002169 is an equidigital number, since it uses as much as digits as its factorization.

1312132002169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 1312132002169 in words is "one trillion, three hundred twelve billion, one hundred thirty-two million, two thousand, one hundred sixty-nine".