13121331121033 has 4 divisors (see below), whose sum is σ = 13121617965568. Its totient is φ = 13121044276500.

The previous prime is 13121331121001. The next prime is 13121331121061. The reversal of 13121331121033 is 33012113312131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13121331121033 - 2⁵ = 13121331121001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13121331120989 and 13121331121007.

It is not an unprimeable number, because it can be changed into a prime (13121331121933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143353641 + ... + 143445142.

It is an arithmetic number, because the mean of its divisors is an integer number (3280404491392).

Almost surely, 2^{13121331121033} is an apocalyptic number.

It is an amenable number.

13121331121033 is a deficient number, since it is larger than the sum of its proper divisors (286844535).

13121331121033 is an equidigital number, since it uses as much as digits as its factorization.

13121331121033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 286844534.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13121331121033 its reverse (33012113312131), we get a palindrome (46133444433164).

The spelling of 13121331121033 in words is "thirteen trillion, one hundred twenty-one billion, three hundred thirty-one million, one hundred twenty-one thousand, thirty-three".