| Base | Representation |
|---|---|
| bin | 1011111011110000110001… |
| … | …1001100000101000011100 |
| 3 | 1201110101110021010210111000 |
| 4 | 2332330030121200220130 |
| 5 | 3204434442233300012 |
| 6 | 43523505054030300 |
| 7 | 2522661603066012 |
| oct | 276741431405034 |
| 9 | 51411407123430 |
| 10 | 13121333103132 |
| 11 | 41a97a9511a41 |
| 12 | 157b003aa8390 |
| 13 | 74244b0cacb7 |
| 14 | 33510c4288b2 |
| 15 | 17b4b16baddc |
| hex | bef0c660a1c |
13121333103132 has 192 divisors, whose sum is σ = 34599809502720. Its totient is φ = 4299434380800.
The previous prime is 13121333103113. The next prime is 13121333103139. The reversal of 13121333103132 is 23130133312131.
13121333103132 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 1 + 33 + 310 + 313 + 2 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 13121333103096 and 13121333103105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13121333103139) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4256026063 + ... + 4256029145.
It is an arithmetic number, because the mean of its divisors is an integer number (180207341160).
Almost surely, 213121333103132 is an apocalyptic number.
13121333103132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13121333103132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17299904751360).
13121333103132 is an abundant number, since it is smaller than the sum of its proper divisors (21478476399588).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13121333103132 is a wasteful number, since it uses less digits than its factorization.
13121333103132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4801 (or 4793 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 27.
Adding to 13121333103132 its reverse (23130133312131), we get a palindrome (36251466415263).
The spelling of 13121333103132 in words is "thirteen trillion, one hundred twenty-one billion, three hundred thirty-three million, one hundred three thousand, one hundred thirty-two".
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