Base | Representation |
---|---|
bin | 10011000110000001011… |
… | …010110011010101000100 |
3 | 11122102212000221222200002 |
4 | 103012001122303111010 |
5 | 132444223343442012 |
6 | 2442442002540432 |
7 | 163540650425522 |
oct | 23060132632504 |
9 | 4572760858602 |
10 | 1312136312132 |
11 | 466523817118 |
12 | 192373967718 |
13 | 96970577819 |
14 | 4771732b312 |
15 | 241e961e7c2 |
hex | 131816b3544 |
1312136312132 has 24 divisors (see below), whose sum is σ = 2299305408120. Its totient is φ = 655192074240.
The previous prime is 1312136312111. The next prime is 1312136312183. The reversal of 1312136312132 is 2312136312131.
It can be written as a sum of positive squares in 4 ways, for example, as 653678718016 + 658457594116 = 808504^2 + 811454^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1312136312095 and 1312136312104.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62900648 + ... + 62921504.
It is an arithmetic number, because the mean of its divisors is an integer number (95804392005).
Almost surely, 21312136312132 is an apocalyptic number.
It is an amenable number.
1312136312132 is a deficient number, since it is larger than the sum of its proper divisors (987169095988).
1312136312132 is a wasteful number, since it uses less digits than its factorization.
1312136312132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41111 (or 41109 counting only the distinct ones).
The product of its digits is 3888, while the sum is 29.
Subtracting 1312136312132 from its reverse (2312136312131), we obtain a palindrome (999999999999).
The spelling of 1312136312132 in words is "one trillion, three hundred twelve billion, one hundred thirty-six million, three hundred twelve thousand, one hundred thirty-two".
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