Base | Representation |
---|---|
bin | 1011111011110001000100… |
… | …1010100011011010011011 |
3 | 1201110101122211121110021012 |
4 | 2332330101022203122123 |
5 | 3204440123221142233 |
6 | 43523521032004135 |
7 | 2522663563556021 |
oct | 276742112433233 |
9 | 51411584543235 |
10 | 13121413068443 |
11 | 41a983a66a079 |
12 | 157b02683064b |
13 | 742461848654 |
14 | 335118cc2711 |
15 | 17b4b8714548 |
hex | bef112a369b |
13121413068443 has 2 divisors, whose sum is σ = 13121413068444. Its totient is φ = 13121413068442.
The previous prime is 13121413068437. The next prime is 13121413068481. The reversal of 13121413068443 is 34486031412131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13121413068443 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13121413068443.
It is not a weakly prime, because it can be changed into another prime (13121413068433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560706534221 + 6560706534222.
It is an arithmetic number, because the mean of its divisors is an integer number (6560706534222).
Almost surely, 213121413068443 is an apocalyptic number.
13121413068443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121413068443 is an equidigital number, since it uses as much as digits as its factorization.
13121413068443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 41.
The spelling of 13121413068443 in words is "thirteen trillion, one hundred twenty-one billion, four hundred thirteen million, sixty-eight thousand, four hundred forty-three".
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