Base | Representation |
---|---|
bin | 1011111011110001000100… |
… | …1010101011011001101011 |
3 | 1201110101122211200010011001 |
4 | 2332330101022223121223 |
5 | 3204440123223214123 |
6 | 43523521032415431 |
7 | 2522663564053303 |
oct | 276742112533153 |
9 | 51411584603131 |
10 | 13121413101163 |
11 | 41a983a691714 |
12 | 157b026847577 |
13 | 74246185a503 |
14 | 335118cd0603 |
15 | 17b4b871e0ad |
hex | bef112ab66b |
13121413101163 has 2 divisors, whose sum is σ = 13121413101164. Its totient is φ = 13121413101162.
The previous prime is 13121413101133. The next prime is 13121413101197. The reversal of 13121413101163 is 36110131412131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13121413101163 - 221 = 13121411004011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13121413101133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560706550581 + 6560706550582.
It is an arithmetic number, because the mean of its divisors is an integer number (6560706550582).
Almost surely, 213121413101163 is an apocalyptic number.
13121413101163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121413101163 is an equidigital number, since it uses as much as digits as its factorization.
13121413101163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 28.
Adding to 13121413101163 its reverse (36110131412131), we get a palindrome (49231544513294).
The spelling of 13121413101163 in words is "thirteen trillion, one hundred twenty-one billion, four hundred thirteen million, one hundred one thousand, one hundred sixty-three".
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