1312141533331 has 2 divisors, whose sum is σ = 1312141533332. Its totient is φ = 1312141533330.

The previous prime is 1312141533299. The next prime is 1312141533361. The reversal of 1312141533331 is 1333351412131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1312141533331 - 2⁵ = 1312141533299 is a prime.

It is a super-2 number, since 2×1312141533331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1312141533293 and 1312141533302.

It is not a weakly prime, because it can be changed into another prime (1312141533361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656070766665 + 656070766666.

It is an arithmetic number, because the mean of its divisors is an integer number (656070766666).

Almost surely, 2^{1312141533331} is an apocalyptic number.

1312141533331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312141533331 is an equidigital number, since it uses as much as digits as its factorization.

1312141533331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9720, while the sum is 31.

Adding to 1312141533331 its reverse (1333351412131), we get a palindrome (2645492945462).

The spelling of 1312141533331 in words is "one trillion, three hundred twelve billion, one hundred forty-one million, five hundred thirty-three thousand, three hundred thirty-one".