Base | Representation |
---|---|
bin | 1011111011110001000111… |
… | …1011101010111010101001 |
3 | 1201110101200201211121112022 |
4 | 2332330101323222322221 |
5 | 3204440140020203413 |
6 | 43523522211554225 |
7 | 2522664111163535 |
oct | 276742173527251 |
9 | 51411621747468 |
10 | 13121425944233 |
11 | 41a9846963922 |
12 | 157b02abbb975 |
13 | 742464406169 |
14 | 33511a8b4bc5 |
15 | 17b4b9909608 |
hex | bef11eeaea9 |
13121425944233 has 2 divisors, whose sum is σ = 13121425944234. Its totient is φ = 13121425944232.
The previous prime is 13121425944229. The next prime is 13121425944343. The reversal of 13121425944233 is 33244952412131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10735924071184 + 2385501873049 = 3276572^2 + 1544507^2 .
It is a cyclic number.
It is not a de Polignac number, because 13121425944233 - 22 = 13121425944229 is a prime.
It is not a weakly prime, because it can be changed into another prime (13121425944203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560712972116 + 6560712972117.
It is an arithmetic number, because the mean of its divisors is an integer number (6560712972117).
Almost surely, 213121425944233 is an apocalyptic number.
It is an amenable number.
13121425944233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121425944233 is an equidigital number, since it uses as much as digits as its factorization.
13121425944233 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 622080, while the sum is 44.
The spelling of 13121425944233 in words is "thirteen trillion, one hundred twenty-one billion, four hundred twenty-five million, nine hundred forty-four thousand, two hundred thirty-three".
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