Base | Representation |
---|---|
bin | 11000011100001100… |
… | …11010000011111011 |
3 | 1020212110100100201110 |
4 | 30032012122003323 |
5 | 203333043300043 |
6 | 10010010251403 |
7 | 643106406531 |
oct | 141606320373 |
9 | 36773310643 |
10 | 13121462523 |
11 | 56237a6004 |
12 | 2662426b63 |
13 | 13115bb510 |
14 | 8c6946151 |
15 | 51be45b33 |
hex | 30e19a0fb |
13121462523 has 32 divisors (see below), whose sum is σ = 19166273280. Its totient is φ = 7935603840.
The previous prime is 13121462509. The next prime is 13121462531. The reversal of 13121462523 is 32526412131.
13121462523 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13121462523 - 213 = 13121454331 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13121462723) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5334868 + ... + 5337326.
It is an arithmetic number, because the mean of its divisors is an integer number (598946040).
Almost surely, 213121462523 is an apocalyptic number.
13121462523 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13121462523 is a deficient number, since it is larger than the sum of its proper divisors (6044810757).
13121462523 is a wasteful number, since it uses less digits than its factorization.
13121462523 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4779.
The product of its digits is 8640, while the sum is 30.
Adding to 13121462523 its reverse (32526412131), we get a palindrome (45647874654).
The spelling of 13121462523 in words is "thirteen billion, one hundred twenty-one million, four hundred sixty-two thousand, five hundred twenty-three".
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