Base | Representation |
---|---|
bin | 10011000110000010100… |
… | …011101101000101011011 |
3 | 11122102220100220220221111 |
4 | 103012002203231011123 |
5 | 132444243242014232 |
6 | 2442443524321151 |
7 | 163541302032526 |
oct | 23060243550533 |
9 | 4572810826844 |
10 | 1312155423067 |
11 | 46653358a485 |
12 | 19237a2431b7 |
13 | 96974509378 |
14 | 47719aa3bbd |
15 | 241eb147047 |
hex | 131828ed15b |
1312155423067 has 2 divisors, whose sum is σ = 1312155423068. Its totient is φ = 1312155423066.
The previous prime is 1312155423053. The next prime is 1312155423097. The reversal of 1312155423067 is 7603245512131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312155423067 - 211 = 1312155421019 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312155423097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656077711533 + 656077711534.
It is an arithmetic number, because the mean of its divisors is an integer number (656077711534).
Almost surely, 21312155423067 is an apocalyptic number.
1312155423067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312155423067 is an equidigital number, since it uses as much as digits as its factorization.
1312155423067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 1312155423067 in words is "one trillion, three hundred twelve billion, one hundred fifty-five million, four hundred twenty-three thousand, sixty-seven".
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