Base | Representation |
---|---|
bin | 111101000110101010… |
… | …0100111100011000011 |
3 | 110112200221121020100221 |
4 | 1322031110213203003 |
5 | 4122214310324303 |
6 | 140140500123511 |
7 | 12323516456221 |
oct | 1721524474303 |
9 | 415627536327 |
10 | 131220011203 |
11 | 50717303656 |
12 | 21521396597 |
13 | c4b2884558 |
14 | 64cb527b11 |
15 | 36300034bd |
hex | 1e8d5278c3 |
131220011203 has 2 divisors, whose sum is σ = 131220011204. Its totient is φ = 131220011202.
The previous prime is 131220011191. The next prime is 131220011227. The reversal of 131220011203 is 302110022131.
It is a weak prime.
It is an emirp because it is prime and its reverse (302110022131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131220011203 is a prime.
It is not a weakly prime, because it can be changed into another prime (131220011243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610005601 + 65610005602.
It is an arithmetic number, because the mean of its divisors is an integer number (65610005602).
Almost surely, 2131220011203 is an apocalyptic number.
131220011203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131220011203 is an equidigital number, since it uses as much as digits as its factorization.
131220011203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 131220011203 its reverse (302110022131), we get a palindrome (433330033334).
The spelling of 131220011203 in words is "one hundred thirty-one billion, two hundred twenty million, eleven thousand, two hundred three".
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