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13122012443143 = 19766609200219
BaseRepresentation
bin1011111011110011010011…
…1000111111001000000111
31201110110012121102211210011
42332330310320333020013
53204442340141140033
643524100322411051
72523014462302102
oct276746470771007
951413177384704
1013122012443143
1141aa017a3016a
12157b173500a87
13742528a85736
14335174745739
1517b50115bccd
hexbef34e3f207

13122012443143 has 4 divisors (see below), whose sum is σ = 13188621643560. Its totient is φ = 13055403242728.

The previous prime is 13122012443107. The next prime is 13122012443159. The reversal of 13122012443143 is 34134421022131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13122012443143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13122012443173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33304599913 + ... + 33304600306.

It is an arithmetic number, because the mean of its divisors is an integer number (3297155410890).

Almost surely, 213122012443143 is an apocalyptic number.

13122012443143 is a deficient number, since it is larger than the sum of its proper divisors (66609200417).

13122012443143 is an equidigital number, since it uses as much as digits as its factorization.

13122012443143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66609200416.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13122012443143 its reverse (34134421022131), we get a palindrome (47256433465274).

The spelling of 13122012443143 in words is "thirteen trillion, one hundred twenty-two billion, twelve million, four hundred forty-three thousand, one hundred forty-three".

Divisors: 1 197 66609200219 13122012443143