Base | Representation |
---|---|
bin | 10011000110000101010… |
… | …101011010010101111011 |
3 | 11122110000121120200100211 |
4 | 103012011111122111323 |
5 | 132444342203223211 |
6 | 2442452311011551 |
7 | 163542406014463 |
oct | 23060525322573 |
9 | 4573017520324 |
10 | 1312202007931 |
11 | 466557908371 |
12 | 192391969bb7 |
13 | 9698106a189 |
14 | 47721d4cba3 |
15 | 24200299e21 |
hex | 1318555a57b |
1312202007931 has 2 divisors, whose sum is σ = 1312202007932. Its totient is φ = 1312202007930.
The previous prime is 1312202007923. The next prime is 1312202007959. The reversal of 1312202007931 is 1397002022131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312202007931 - 23 = 1312202007923 is a prime.
It is a super-2 number, since 2×13122020079312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1312202007893 and 1312202007902.
It is not a weakly prime, because it can be changed into another prime (1312202007911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656101003965 + 656101003966.
It is an arithmetic number, because the mean of its divisors is an integer number (656101003966).
Almost surely, 21312202007931 is an apocalyptic number.
1312202007931 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312202007931 is an equidigital number, since it uses as much as digits as its factorization.
1312202007931 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4536, while the sum is 31.
The spelling of 1312202007931 in words is "one trillion, three hundred twelve billion, two hundred two million, seven thousand, nine hundred thirty-one".
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