Base | Representation |
---|---|
bin | 111101000110101010… |
… | …1011000011010000110 |
3 | 110112200221222101220012 |
4 | 1322031111120122012 |
5 | 4122214333230314 |
6 | 140140504310222 |
7 | 12323521251542 |
oct | 1721525303206 |
9 | 415627871805 |
10 | 131220211334 |
11 | 5071742aa53 |
12 | 21521472372 |
13 | c4b2924684 |
14 | 64cb57aa22 |
15 | 363004293e |
hex | 1e8d558686 |
131220211334 has 4 divisors (see below), whose sum is σ = 196830317004. Its totient is φ = 65610105666.
The previous prime is 131220211327. The next prime is 131220211357. The reversal of 131220211334 is 433112022131.
It is a semiprime because it is the product of two primes.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32805052832 + ... + 32805052835.
It is an arithmetic number, because the mean of its divisors is an integer number (49207579251).
Almost surely, 2131220211334 is an apocalyptic number.
131220211334 is a deficient number, since it is larger than the sum of its proper divisors (65610105670).
131220211334 is an equidigital number, since it uses as much as digits as its factorization.
131220211334 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65610105669.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 131220211334 its reverse (433112022131), we get a palindrome (564332233465).
The spelling of 131220211334 in words is "one hundred thirty-one billion, two hundred twenty million, two hundred eleven thousand, three hundred thirty-four".
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