Base | Representation |
---|---|
bin | 1011111011110011011010… |
… | …0010100010000011000110 |
3 | 1201110110021112111112100210 |
4 | 2332330312202202003012 |
5 | 3204442414232030202 |
6 | 43524103151420250 |
7 | 2523015246416223 |
oct | 276746642420306 |
9 | 51413245445323 |
10 | 13122040111302 |
11 | 41aa031608711 |
12 | 157b180824686 |
13 | 742531722225 |
14 | 3351782a894a |
15 | 17b5037c4c6c |
hex | bef368a20c6 |
13122040111302 has 16 divisors (see below), whose sum is σ = 26244711331632. Its totient is φ = 4373908185600.
The previous prime is 13122040111289. The next prime is 13122040111339. The reversal of 13122040111302 is 20311104022131.
13122040111302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26025699 + ... + 26525102.
It is an arithmetic number, because the mean of its divisors is an integer number (1640294458227).
Almost surely, 213122040111302 is an apocalyptic number.
13122040111302 is an abundant number, since it is smaller than the sum of its proper divisors (13122671220330).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122040111302 is a wasteful number, since it uses less digits than its factorization.
13122040111302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52592423.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 13122040111302 its reverse (20311104022131), we get a palindrome (33433144133433).
The spelling of 13122040111302 in words is "thirteen trillion, one hundred twenty-two billion, forty million, one hundred eleven thousand, three hundred two".
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