1312204023131 has 2 divisors, whose sum is σ = 1312204023132. Its totient is φ = 1312204023130.

The previous prime is 1312204023061. The next prime is 1312204023149. The reversal of 1312204023131 is 1313204022131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1312204023131 - 2¹⁴ = 1312204006747 is a prime.

It is a super-3 number, since 3×1312204023131³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1312204023097 and 1312204023106.

It is not a weakly prime, because it can be changed into another prime (1312204023931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656102011565 + 656102011566.

It is an arithmetic number, because the mean of its divisors is an integer number (656102011566).

Almost surely, 2^{1312204023131} is an apocalyptic number.

1312204023131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312204023131 is an equidigital number, since it uses as much as digits as its factorization.

1312204023131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1312204023131 its reverse (1313204022131), we get a palindrome (2625408045262).

The spelling of 1312204023131 in words is "one trillion, three hundred twelve billion, two hundred four million, twenty-three thousand, one hundred thirty-one".