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131220420433 = 2347682317791
BaseRepresentation
bin111101000110101011…
…0001011011101010001
3110112200222101000201121
41322031112023131101
54122214411423213
6140140513002241
712323523112264
oct1721526133521
9415628330647
10131220420433
1150717563063
1221521553381
13c4b29988bb
1464cb5d2cdb
15363008488d
hex1e8d58b751

131220420433 has 16 divisors (see below), whose sum is σ = 139867324416. Its totient is φ = 122819740560.

The previous prime is 131220420389. The next prime is 131220420449. The reversal of 131220420433 is 334024022131.

It is not a de Polignac number, because 131220420433 - 213 = 131220412241 is a prime.

It is a super-2 number, since 2×1312204204332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131220420398 and 131220420407.

It is not an unprimeable number, because it can be changed into a prime (131220429433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7366768 + ... + 7384558.

It is an arithmetic number, because the mean of its divisors is an integer number (8741707776).

Almost surely, 2131220420433 is an apocalyptic number.

It is an amenable number.

131220420433 is a deficient number, since it is larger than the sum of its proper divisors (8646903983).

131220420433 is a wasteful number, since it uses less digits than its factorization.

131220420433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24684.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 131220420433 its reverse (334024022131), we get a palindrome (465244442564).

The spelling of 131220420433 in words is "one hundred thirty-one billion, two hundred twenty million, four hundred twenty thousand, four hundred thirty-three".

Divisors: 1 23 47 1081 6823 17791 156929 320681 409193 836177 7375663 19232071 121387993 2791923839 5705235671 131220420433