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1312210307 is a prime number
BaseRepresentation
bin100111000110110…
…1011110110000011
310101110011012010202
41032031223312003
510141411212212
6334113115415
744342414012
oct11615536603
93343135122
101312210307
11613788031
12307558b6b
1317bb21905
14c63bca79
157a3030c2
hex4e36bd83

1312210307 has 2 divisors, whose sum is σ = 1312210308. Its totient is φ = 1312210306.

The previous prime is 1312210267. The next prime is 1312210379. The reversal of 1312210307 is 7030122131.

It is a weak prime.

It is an emirp because it is prime and its reverse (7030122131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312210307 - 226 = 1245101443 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312210507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656105153 + 656105154.

It is an arithmetic number, because the mean of its divisors is an integer number (656105154).

Almost surely, 21312210307 is an apocalyptic number.

1312210307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312210307 is an equidigital number, since it uses as much as digits as its factorization.

1312210307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 20.

The square root of 1312210307 is about 36224.4435015916. The cubic root of 1312210307 is about 1094.7992256455.

Adding to 1312210307 its reverse (7030122131), we get a palindrome (8342332438).

The spelling of 1312210307 in words is "one billion, three hundred twelve million, two hundred ten thousand, three hundred seven".