Base | Representation |
---|---|
bin | 11101110101100001010111… |
… | …001011010111000101101011 |
3 | 122012121122010020212102200111 |
4 | 131311201113023113011223 |
5 | 114144412212134021324 |
6 | 1143030122400515151 |
7 | 36432266140420453 |
oct | 3565412713270553 |
9 | 565548106772614 |
10 | 131221303423339 |
11 | 388a1707939608 |
12 | 1287369901bab7 |
13 | 582b1675b0a1c |
14 | 2459205b40d63 |
15 | 1028579669794 |
hex | 7758572d716b |
131221303423339 has 2 divisors, whose sum is σ = 131221303423340. Its totient is φ = 131221303423338.
The previous prime is 131221303423187. The next prime is 131221303423369. The reversal of 131221303423339 is 933324303122131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131221303423339 - 29 = 131221303422827 is a prime.
It is a super-3 number, since 3×1312213034233393 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (131221303423369) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610651711669 + 65610651711670.
It is an arithmetic number, because the mean of its divisors is an integer number (65610651711670).
Almost surely, 2131221303423339 is an apocalyptic number.
131221303423339 is a deficient number, since it is larger than the sum of its proper divisors (1).
131221303423339 is an equidigital number, since it uses as much as digits as its factorization.
131221303423339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 209952, while the sum is 40.
The spelling of 131221303423339 in words is "one hundred thirty-one trillion, two hundred twenty-one billion, three hundred three million, four hundred twenty-three thousand, three hundred thirty-nine".
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