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1312214022421 = 5472398928743
BaseRepresentation
bin10011000110000110000…
…011001111100100010101
311122110001110012002010221
4103012012003033210111
5132444403242204141
62442453420314341
7163542613104241
oct23060603174425
94573043162127
101312214022421
11466563673aa5
121923959a29b1
13969836b5943
1447723799421
152420136ebd1
hex131860cf915

1312214022421 has 4 divisors (see below), whose sum is σ = 1314612951712. Its totient is φ = 1309815093132.

The previous prime is 1312214022407. The next prime is 1312214022437. The reversal of 1312214022421 is 1242204122131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312214022421 - 27 = 1312214022293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312214022491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1199463825 + ... + 1199464918.

It is an arithmetic number, because the mean of its divisors is an integer number (328653237928).

Almost surely, 21312214022421 is an apocalyptic number.

It is an amenable number.

1312214022421 is a deficient number, since it is larger than the sum of its proper divisors (2398929291).

1312214022421 is an equidigital number, since it uses as much as digits as its factorization.

1312214022421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2398929290.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1312214022421 its reverse (1242204122131), we get a palindrome (2554418144552).

The spelling of 1312214022421 in words is "one trillion, three hundred twelve billion, two hundred fourteen million, twenty-two thousand, four hundred twenty-one".

Divisors: 1 547 2398928743 1312214022421