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131221403214000 = 243531110119685179
BaseRepresentation
bin11101110101100001011101…
…001000000010000010110000
3122012121122101012122022201220
4131311201131020002002300
5114144412413210322000
61143030140323425040
736432301461551361
oct3565413510020260
9565548335568656
10131221403214000
11388a17591a7830
1212873706525180
13582b182180158
1424592150b9b68
1510285832cc1a0
hex77585d2020b0

131221403214000 has 320 divisors, whose sum is σ = 466087109230080. Its totient is φ = 31496284800000.

The previous prime is 131221403213959. The next prime is 131221403214001. The reversal of 131221403214000 is 412304122131.

It is a super-2 number, since 2×1312214032140002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is not an unprimeable number, because it can be changed into a prime (131221403214001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3176590 + ... + 16508589.

It is an arithmetic number, because the mean of its divisors is an integer number (1456522216344).

Almost surely, 2131221403214000 is an apocalyptic number.

131221403214000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131221403214000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (233043554615040).

131221403214000 is an abundant number, since it is smaller than the sum of its proper divisors (334865706016080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131221403214000 is a wasteful number, since it uses less digits than its factorization.

131221403214000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19685317 (or 19685301 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 131221403214000 its reverse (412304122131), we get a palindrome (131633707336131).

The spelling of 131221403214000 in words is "one hundred thirty-one trillion, two hundred twenty-one billion, four hundred three million, two hundred fourteen thousand".