Base | Representation |
---|---|
bin | 10011000110000110011… |
… | …010100001010111100011 |
3 | 11122110001212200002211011 |
4 | 103012012122201113203 |
5 | 132444411322442033 |
6 | 2442454155201351 |
7 | 163543016011051 |
oct | 23060632412743 |
9 | 4573055602734 |
10 | 1312220124643 |
11 | 46656706175a |
12 | 192397a46257 |
13 | 96984a4131c |
14 | 477245071d1 |
15 | 24201b77ccd |
hex | 131866a15e3 |
1312220124643 has 2 divisors, whose sum is σ = 1312220124644. Its totient is φ = 1312220124642.
The previous prime is 1312220124557. The next prime is 1312220124659. The reversal of 1312220124643 is 3464210222131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312220124643 - 229 = 1311683253731 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312220124673) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656110062321 + 656110062322.
It is an arithmetic number, because the mean of its divisors is an integer number (656110062322).
Almost surely, 21312220124643 is an apocalyptic number.
1312220124643 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312220124643 is an equidigital number, since it uses as much as digits as its factorization.
1312220124643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1312220124643 its reverse (3464210222131), we get a palindrome (4776430346774).
The spelling of 1312220124643 in words is "one trillion, three hundred twelve billion, two hundred twenty million, one hundred twenty-four thousand, six hundred forty-three".
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