131222102111 has 4 divisors (see below), whose sum is σ = 138941049312. Its totient is φ = 123503154912.

The previous prime is 131222102087. The next prime is 131222102161. The reversal of 131222102111 is 111201222131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111201222131 = 140627 ⋅790753.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131222102111 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 7718947183 = 131222102111 / (1 + 3 + 1 + 2 + 2 + 2 + 1 + 0 + 2 + 1 + 1 + 1).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131222102111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131222102161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3859473575 + ... + 3859473608.

It is an arithmetic number, because the mean of its divisors is an integer number (34735262328).

Almost surely, 2^131222102111 is an apocalyptic number.

131222102111 is a deficient number, since it is larger than the sum of its proper divisors (7718947201).

131222102111 is an equidigital number, since it uses as much as digits as its factorization.

131222102111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7718947200.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 131222102111 its reverse (111201222131), we get a palindrome (242423324242).

The spelling of 131222102111 in words is "one hundred thirty-one billion, two hundred twenty-two million, one hundred two thousand, one hundred eleven".