Base | Representation |
---|---|
bin | 11101110101100010000111… |
… | …111011000000111111110011 |
3 | 122012121201020020200220201122 |
4 | 131311202013323000333303 |
5 | 114144420401013102011 |
6 | 1143030335453052455 |
7 | 36432325330534502 |
oct | 3565420773007763 |
9 | 565551206626648 |
10 | 131222121222131 |
11 | 388a1a97526985 |
12 | 12873886a8712b |
13 | 582b267b56134 |
14 | 24592825c0839 |
15 | 10285c635a3db |
hex | 775887ec0ff3 |
131222121222131 has 2 divisors, whose sum is σ = 131222121222132. Its totient is φ = 131222121222130.
The previous prime is 131222121222109. The next prime is 131222121222161.
131222121222131 is nontrivially palindromic in base 10.
It is a weak prime.
It is a palprime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131222121222131 is a prime.
It is a super-2 number, since 2×1312221212221312 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131222121222131.
It is not a weakly prime, because it can be changed into another prime (131222121222161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611060611065 + 65611060611066.
It is an arithmetic number, because the mean of its divisors is an integer number (65611060611066).
Almost surely, 2131222121222131 is an apocalyptic number.
131222121222131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222121222131 is an equidigital number, since it uses as much as digits as its factorization.
131222121222131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1152, while the sum is 26.
The spelling of 131222121222131 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, one hundred twenty-one million, two hundred twenty-two thousand, one hundred thirty-one".
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