Base | Representation |
---|---|
bin | 10011000110000110100… |
… | …010000011101010111001 |
3 | 11122110002000101110201012 |
4 | 103012012202003222321 |
5 | 132444412324201103 |
6 | 2442454305403305 |
7 | 163543041546416 |
oct | 23060642035271 |
9 | 4573060343635 |
10 | 1312222100153 |
11 | 466568190a08 |
12 | 192398639535 |
13 | 96985283573 |
14 | 4772489d10d |
15 | 24201e182d8 |
hex | 13186883ab9 |
1312222100153 has 2 divisors, whose sum is σ = 1312222100154. Its totient is φ = 1312222100152.
The previous prime is 1312222100113. The next prime is 1312222100171. The reversal of 1312222100153 is 3510012222131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1273076686249 + 39145413904 = 1128307^2 + 197852^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312222100153 - 234 = 1295042230969 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1312222100113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656111050076 + 656111050077.
It is an arithmetic number, because the mean of its divisors is an integer number (656111050077).
Almost surely, 21312222100153 is an apocalyptic number.
It is an amenable number.
1312222100153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312222100153 is an equidigital number, since it uses as much as digits as its factorization.
1312222100153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 1312222100153 its reverse (3510012222131), we get a palindrome (4822234322284).
The spelling of 1312222100153 in words is "one trillion, three hundred twelve billion, two hundred twenty-two million, one hundred thousand, one hundred fifty-three".
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