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1312222100153 is a prime number
BaseRepresentation
bin10011000110000110100…
…010000011101010111001
311122110002000101110201012
4103012012202003222321
5132444412324201103
62442454305403305
7163543041546416
oct23060642035271
94573060343635
101312222100153
11466568190a08
12192398639535
1396985283573
144772489d10d
1524201e182d8
hex13186883ab9

1312222100153 has 2 divisors, whose sum is σ = 1312222100154. Its totient is φ = 1312222100152.

The previous prime is 1312222100113. The next prime is 1312222100171. The reversal of 1312222100153 is 3510012222131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1273076686249 + 39145413904 = 1128307^2 + 197852^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312222100153 - 234 = 1295042230969 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1312222100113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656111050076 + 656111050077.

It is an arithmetic number, because the mean of its divisors is an integer number (656111050077).

Almost surely, 21312222100153 is an apocalyptic number.

It is an amenable number.

1312222100153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312222100153 is an equidigital number, since it uses as much as digits as its factorization.

1312222100153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 1312222100153 its reverse (3510012222131), we get a palindrome (4822234322284).

The spelling of 1312222100153 in words is "one trillion, three hundred twelve billion, two hundred twenty-two million, one hundred thousand, one hundred fifty-three".