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131222332420979 is a prime number
BaseRepresentation
bin11101110101100010010100…
…100000101011001101110011
3122012121201202222002221002012
4131311202110200223031303
5114144421314044432404
61143030412435513135
736432333503643542
oct3565422440531563
9565551688087065
10131222332420979
11388a2095768788
12128739257587ab
13582b29c831877
1424592a267a159
1510285d9b77a6e
hex77589482b373

131222332420979 has 2 divisors, whose sum is σ = 131222332420980. Its totient is φ = 131222332420978.

The previous prime is 131222332420937. The next prime is 131222332421027. The reversal of 131222332420979 is 979024233222131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131222332420979 is a prime.

It is a super-3 number, since 3×1312223324209793 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (131222332425979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611166210489 + 65611166210490.

It is an arithmetic number, because the mean of its divisors is an integer number (65611166210490).

Almost surely, 2131222332420979 is an apocalyptic number.

131222332420979 is a deficient number, since it is larger than the sum of its proper divisors (1).

131222332420979 is an equidigital number, since it uses as much as digits as its factorization.

131222332420979 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1959552, while the sum is 50.

The spelling of 131222332420979 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, three hundred thirty-two million, four hundred twenty thousand, nine hundred seventy-nine".