Base | Representation |
---|---|
bin | 10011000110000110110… |
… | …001010111001000111111 |
3 | 11122110002021221022000110 |
4 | 103012012301113020333 |
5 | 132444414341041223 |
6 | 2442454531401103 |
7 | 163543120626066 |
oct | 23060661271077 |
9 | 4573067838013 |
10 | 1312226112063 |
11 | 46656a481139 |
12 | 192399a53193 |
13 | 96986059689 |
14 | 477252251dd |
15 | 2420245bd93 |
hex | 13186c5723f |
1312226112063 has 4 divisors (see below), whose sum is σ = 1749634816088. Its totient is φ = 874817408040.
The previous prime is 1312226112059. The next prime is 1312226112077. The reversal of 1312226112063 is 3602116222131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1312226112063 - 22 = 1312226112059 is a prime.
It is a super-3 number, since 3×13122261120633 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1312226112063.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312226112013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218704352008 + ... + 218704352013.
It is an arithmetic number, because the mean of its divisors is an integer number (437408704022).
Almost surely, 21312226112063 is an apocalyptic number.
1312226112063 is a deficient number, since it is larger than the sum of its proper divisors (437408704025).
1312226112063 is an equidigital number, since it uses as much as digits as its factorization.
1312226112063 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 437408704024.
The product of its (nonzero) digits is 5184, while the sum is 30.
The spelling of 1312226112063 in words is "one trillion, three hundred twelve billion, two hundred twenty-six million, one hundred twelve thousand, sixty-three".
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