13122301004014 has 4 divisors (see below), whose sum is σ = 19683451506024. Its totient is φ = 6561150502006.

The previous prime is 13122301003961. The next prime is 13122301004027. The reversal of 13122301004014 is 41040010322131.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×13122301004014³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280575251002 + ... + 3280575251005.

It is an arithmetic number, because the mean of its divisors is an integer number (4920862876506).

Almost surely, 2^{13122301004014} is an apocalyptic number.

13122301004014 is a deficient number, since it is larger than the sum of its proper divisors (6561150502010).

13122301004014 is an equidigital number, since it uses as much as digits as its factorization.

13122301004014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6561150502009.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13122301004014 its reverse (41040010322131), we get a palindrome (54162311326145).

The spelling of 13122301004014 in words is "thirteen trillion, one hundred twenty-two billion, three hundred one million, four thousand, fourteen".