Base | Representation |
---|---|
bin | 11101110101100010111101… |
… | …101011110111100111100110 |
3 | 122012121210120002222012212101 |
4 | 131311202331223313213212 |
5 | 114144424222421034342 |
6 | 1143031005154042314 |
7 | 36432356562440452 |
oct | 3565427553674746 |
9 | 565553502865771 |
10 | 131223023221222 |
11 | 388a240a6a4179 |
12 | 12873a98b7939a |
13 | 582b37c99c6ca |
14 | 245932a2db662 |
15 | 102862a62e3b7 |
hex | 7758bdaf79e6 |
131223023221222 has 4 divisors (see below), whose sum is σ = 196834534831836. Its totient is φ = 65611511610610.
The previous prime is 131223023221217. The next prime is 131223023221249. The reversal of 131223023221222 is 222122320322131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32805755805304 + ... + 32805755805307.
It is an arithmetic number, because the mean of its divisors is an integer number (49208633707959).
Almost surely, 2131223023221222 is an apocalyptic number.
131223023221222 is a deficient number, since it is larger than the sum of its proper divisors (65611511610614).
131223023221222 is an equidigital number, since it uses as much as digits as its factorization.
131223023221222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65611511610613.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 131223023221222 its reverse (222122320322131), we get a palindrome (353345343543353).
The spelling of 131223023221222 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, twenty-three million, two hundred twenty-one thousand, two hundred twenty-two".
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