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1312230340103 = 1518690267153
BaseRepresentation
bin10011000110000111000…
…001011111011000000111
311122110002120220002210112
4103012013001133120013
5132444421431340403
62442455202143235
7163543201565534
oct23060701373007
94573076802715
101312230340103
114665718a9791
1219239b351b1b
1396986ba9c87
1447725a05d8b
15242029e49d8
hex1318705f607

1312230340103 has 4 divisors (see below), whose sum is σ = 1320920607408. Its totient is φ = 1303540072800.

The previous prime is 1312230340061. The next prime is 1312230340111. The reversal of 1312230340103 is 3010430322131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1312230340103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312230340703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4345133426 + ... + 4345133727.

It is an arithmetic number, because the mean of its divisors is an integer number (330230151852).

Almost surely, 21312230340103 is an apocalyptic number.

1312230340103 is a deficient number, since it is larger than the sum of its proper divisors (8690267305).

1312230340103 is an equidigital number, since it uses as much as digits as its factorization.

1312230340103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8690267304.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1312230340103 its reverse (3010430322131), we get a palindrome (4322660662234).

The spelling of 1312230340103 in words is "one trillion, three hundred twelve billion, two hundred thirty million, three hundred forty thousand, one hundred three".

Divisors: 1 151 8690267153 1312230340103