Base | Representation |
---|---|
bin | 10011000110000111000… |
… | …001011111100001011111 |
3 | 11122110002120220010121202 |
4 | 103012013001133201133 |
5 | 132444421431400303 |
6 | 2442455202150115 |
7 | 163543201600352 |
oct | 23060701374137 |
9 | 4573076803552 |
10 | 1312230340703 |
11 | 4665718aa187 |
12 | 19239b35233b |
13 | 96986baa329 |
14 | 47725a06299 |
15 | 242029e4c88 |
hex | 1318705f85f |
1312230340703 has 2 divisors, whose sum is σ = 1312230340704. Its totient is φ = 1312230340702.
The previous prime is 1312230340667. The next prime is 1312230340717. The reversal of 1312230340703 is 3070430322131.
It is a strong prime.
It is an emirp because it is prime and its reverse (3070430322131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312230340703 - 226 = 1312163231839 is a prime.
It is a super-2 number, since 2×13122303407032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312230348703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656115170351 + 656115170352.
It is an arithmetic number, because the mean of its divisors is an integer number (656115170352).
Almost surely, 21312230340703 is an apocalyptic number.
1312230340703 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312230340703 is an equidigital number, since it uses as much as digits as its factorization.
1312230340703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 29.
Adding to 1312230340703 its reverse (3070430322131), we get a palindrome (4382660662834).
The spelling of 1312230340703 in words is "one trillion, three hundred twelve billion, two hundred thirty million, three hundred forty thousand, seven hundred three".
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