Base | Representation |
---|---|
bin | 10011000110000111000… |
… | …100100011101110001011 |
3 | 11122110002122101221222202 |
4 | 103012013010203232023 |
5 | 132444422133104311 |
6 | 2442455231310415 |
7 | 163543211455322 |
oct | 23060704435613 |
9 | 4573078357882 |
10 | 1312231144331 |
11 | 4665722a8a38 |
12 | 19239b67b40b |
13 | 969870cc053 |
14 | 47725b750b9 |
15 | 24202b02e3b |
hex | 13187123b8b |
1312231144331 has 2 divisors, whose sum is σ = 1312231144332. Its totient is φ = 1312231144330.
The previous prime is 1312231144283. The next prime is 1312231144337. The reversal of 1312231144331 is 1334411322131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312231144331 - 230 = 1311157402507 is a prime.
It is a super-2 number, since 2×13122311443312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1312231144294 and 1312231144303.
It is not a weakly prime, because it can be changed into another prime (1312231144337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656115572165 + 656115572166.
It is an arithmetic number, because the mean of its divisors is an integer number (656115572166).
Almost surely, 21312231144331 is an apocalyptic number.
1312231144331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312231144331 is an equidigital number, since it uses as much as digits as its factorization.
1312231144331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 29.
Adding to 1312231144331 its reverse (1334411322131), we get a palindrome (2646642466462).
The spelling of 1312231144331 in words is "one trillion, three hundred twelve billion, two hundred thirty-one million, one hundred forty-four thousand, three hundred thirty-one".
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