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1312231144331 is a prime number
BaseRepresentation
bin10011000110000111000…
…100100011101110001011
311122110002122101221222202
4103012013010203232023
5132444422133104311
62442455231310415
7163543211455322
oct23060704435613
94573078357882
101312231144331
114665722a8a38
1219239b67b40b
13969870cc053
1447725b750b9
1524202b02e3b
hex13187123b8b

1312231144331 has 2 divisors, whose sum is σ = 1312231144332. Its totient is φ = 1312231144330.

The previous prime is 1312231144283. The next prime is 1312231144337. The reversal of 1312231144331 is 1334411322131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1312231144331 - 230 = 1311157402507 is a prime.

It is a super-2 number, since 2×13122311443312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1312231144294 and 1312231144303.

It is not a weakly prime, because it can be changed into another prime (1312231144337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656115572165 + 656115572166.

It is an arithmetic number, because the mean of its divisors is an integer number (656115572166).

Almost surely, 21312231144331 is an apocalyptic number.

1312231144331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312231144331 is an equidigital number, since it uses as much as digits as its factorization.

1312231144331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 29.

Adding to 1312231144331 its reverse (1334411322131), we get a palindrome (2646642466462).

The spelling of 1312231144331 in words is "one trillion, three hundred twelve billion, two hundred thirty-one million, one hundred forty-four thousand, three hundred thirty-one".