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131223214012489 is a prime number
BaseRepresentation
bin11101110101100011001001…
…000011101011100001001001
3122012121211001101222102021121
4131311203021003223201021
5114144430120241344424
61143031040131235241
736432364400232304
oct3565431103534111
9565554041872247
10131223214012489
11388a24a8367505
1212873b30a48b21
13582b3b0381351
1424593477a3b3b
15102863c269ee4
hex7758c90eb849

131223214012489 has 2 divisors, whose sum is σ = 131223214012490. Its totient is φ = 131223214012488.

The previous prime is 131223214012483. The next prime is 131223214012511. The reversal of 131223214012489 is 984210412322131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123585132103225 + 7638081909264 = 11116885^2 + 2763708^2 .

It is an emirp because it is prime and its reverse (984210412322131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131223214012489 - 29 = 131223214011977 is a prime.

It is not a weakly prime, because it can be changed into another prime (131223214012483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611607006244 + 65611607006245.

It is an arithmetic number, because the mean of its divisors is an integer number (65611607006245).

Almost surely, 2131223214012489 is an apocalyptic number.

It is an amenable number.

131223214012489 is a deficient number, since it is larger than the sum of its proper divisors (1).

131223214012489 is an equidigital number, since it uses as much as digits as its factorization.

131223214012489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 165888, while the sum is 43.

The spelling of 131223214012489 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, two hundred fourteen million, twelve thousand, four hundred eighty-nine".