Search a number
-
+
13122322021057 is a prime number
BaseRepresentation
bin1011111011110100011101…
…0101111011101011000001
31201110111000011222000211211
42332331013111323223001
53204444003414133212
643524151142010121
72523025241542444
oct276750725735301
951414004860754
1013122322021057
1141aa166756687
12157b23b116941
13742577c57c32
143351a38cd65b
1517b51d40d9a7
hexbef4757bac1

13122322021057 has 2 divisors, whose sum is σ = 13122322021058. Its totient is φ = 13122322021056.

The previous prime is 13122322021013. The next prime is 13122322021073. The reversal of 13122322021057 is 75012022322131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7755088761616 + 5367233259441 = 2784796^2 + 2316729^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13122322021057 is a prime.

It is not a weakly prime, because it can be changed into another prime (13122322021087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561161010528 + 6561161010529.

It is an arithmetic number, because the mean of its divisors is an integer number (6561161010529).

Almost surely, 213122322021057 is an apocalyptic number.

It is an amenable number.

13122322021057 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122322021057 is an equidigital number, since it uses as much as digits as its factorization.

13122322021057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 13122322021057 its reverse (75012022322131), we get a palindrome (88134344343188).

The spelling of 13122322021057 in words is "thirteen trillion, one hundred twenty-two billion, three hundred twenty-two million, twenty-one thousand, fifty-seven".