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1312232231137 is a prime number
BaseRepresentation
bin10011000110000111001…
…000101101000011100001
311122110002201110011210211
4103012013020231003201
5132444422422344022
62442455310454121
7163543223633002
oct23060710550341
94573081404724
101312232231137
11466572980523
1219239bb04341
13969873bc929
1447725d791a9
1524202c69e77
hex1318722d0e1

1312232231137 has 2 divisors, whose sum is σ = 1312232231138. Its totient is φ = 1312232231136.

The previous prime is 1312232231099. The next prime is 1312232231143. The reversal of 1312232231137 is 7311322322131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 663677432896 + 648554798241 = 814664^2 + 805329^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312232231137 - 223 = 1312223842529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312232231099 and 1312232231108.

It is not a weakly prime, because it can be changed into another prime (1312232231837) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656116115568 + 656116115569.

It is an arithmetic number, because the mean of its divisors is an integer number (656116115569).

Almost surely, 21312232231137 is an apocalyptic number.

It is an amenable number.

1312232231137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312232231137 is an equidigital number, since it uses as much as digits as its factorization.

1312232231137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9072, while the sum is 31.

Adding to 1312232231137 its reverse (7311322322131), we get a palindrome (8623554553268).

The spelling of 1312232231137 in words is "one trillion, three hundred twelve billion, two hundred thirty-two million, two hundred thirty-one thousand, one hundred thirty-seven".