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131223310303 = 588312230513
BaseRepresentation
bin111101000110110000…
…1001100111111011111
3110112201011210211212211
41322031201030333133
54122221131412203
6140141054541251
712323556506461
oct1721541147737
9415634724784
10131223310303
1150719157288
1221522507827
13c4b346b097
1464cbb46131
153630455c6d
hex1e8d84cfdf

131223310303 has 4 divisors (see below), whose sum is σ = 131225599648. Its totient is φ = 131221020960.

The previous prime is 131223310297. The next prime is 131223310307. The reversal of 131223310303 is 303013322131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131223310303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131223310307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1056426 + ... + 1174087.

It is an arithmetic number, because the mean of its divisors is an integer number (32806399912).

Almost surely, 2131223310303 is an apocalyptic number.

131223310303 is a deficient number, since it is larger than the sum of its proper divisors (2289345).

131223310303 is an equidigital number, since it uses as much as digits as its factorization.

131223310303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2289344.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 131223310303 its reverse (303013322131), we get a palindrome (434236632434).

The spelling of 131223310303 in words is "one hundred thirty-one billion, two hundred twenty-three million, three hundred ten thousand, three hundred three".

Divisors: 1 58831 2230513 131223310303