Base | Representation |
---|---|
bin | 10011000110000111011… |
… | …000001000011011000101 |
3 | 11122110010000001122111020 |
4 | 103012013120020123011 |
5 | 132444424441303042 |
6 | 2442455533301353 |
7 | 163543303205565 |
oct | 23060730103305 |
9 | 4573100048436 |
10 | 1312236275397 |
11 | 466575192a93 |
12 | 1923a1334859 |
13 | 969881a7698 |
14 | 4772670cda5 |
15 | 242032b83ec |
hex | 131876086c5 |
1312236275397 has 32 divisors (see below), whose sum is σ = 1928702028672. Its totient is φ = 790136653824.
The previous prime is 1312236275291. The next prime is 1312236275401. The reversal of 1312236275397 is 7935726322131.
It is not a de Polignac number, because 1312236275397 - 216 = 1312236209861 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312236275797) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4625323 + ... + 4900824.
It is an arithmetic number, because the mean of its divisors is an integer number (60271938396).
Almost surely, 21312236275397 is an apocalyptic number.
1312236275397 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
1312236275397 is a deficient number, since it is larger than the sum of its proper divisors (616465753275).
1312236275397 is a wasteful number, since it uses less digits than its factorization.
1312236275397 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9526277.
The product of its digits is 2857680, while the sum is 51.
The spelling of 1312236275397 in words is "one trillion, three hundred twelve billion, two hundred thirty-six million, two hundred seventy-five thousand, three hundred ninety-seven".
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