Base | Representation |
---|---|
bin | 1011111011110100110010… |
… | …1010111000101001101011 |
3 | 1201110111020102010221102011 |
4 | 2332331030222320221223 |
5 | 3204444144304243122 |
6 | 43524204053420351 |
7 | 2523030405340024 |
oct | 276751452705153 |
9 | 51414212127364 |
10 | 13122411399787 |
11 | 41aa2021531a8 |
12 | 157b26503a6b7 |
13 | 742590620161 |
14 | 3351b1717c4b |
15 | 17b5261b6377 |
hex | bef4cab8a6b |
13122411399787 has 2 divisors, whose sum is σ = 13122411399788. Its totient is φ = 13122411399786.
The previous prime is 13122411399737. The next prime is 13122411399841. The reversal of 13122411399787 is 78799311422131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13122411399787 is a prime.
It is not a weakly prime, because it can be changed into another prime (13122411399737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561205699893 + 6561205699894.
It is an arithmetic number, because the mean of its divisors is an integer number (6561205699894).
Almost surely, 213122411399787 is an apocalyptic number.
13122411399787 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122411399787 is an equidigital number, since it uses as much as digits as its factorization.
13122411399787 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4572288, while the sum is 58.
The spelling of 13122411399787 in words is "thirteen trillion, one hundred twenty-two billion, four hundred eleven million, three hundred ninety-nine thousand, seven hundred eighty-seven".
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