1312241200133 has 4 divisors (see below), whose sum is σ = 1312449135648. Its totient is φ = 1312033264620.

The previous prime is 1312241200069. The next prime is 1312241200141. The reversal of 1312241200133 is 3310021422131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312241200133 - 2⁶ = 1312241200069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312241200099 and 1312241200108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312241260133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103958291 + ... + 103970912.

It is an arithmetic number, because the mean of its divisors is an integer number (328112283912).

Almost surely, 2^{1312241200133} is an apocalyptic number.

It is an amenable number.

1312241200133 is a deficient number, since it is larger than the sum of its proper divisors (207935515).

1312241200133 is an equidigital number, since it uses as much as digits as its factorization.

1312241200133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 207935514.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1312241200133 its reverse (3310021422131), we get a palindrome (4622262622264).

The spelling of 1312241200133 in words is "one trillion, three hundred twelve billion, two hundred forty-one million, two hundred thousand, one hundred thirty-three".