1312241260133 has 2 divisors, whose sum is σ = 1312241260134. Its totient is φ = 1312241260132.

The previous prime is 1312241260091. The next prime is 1312241260147. The reversal of 1312241260133 is 3310621422131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 830608036129 + 481633224004 = 911377^2 + 693998^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312241260133 - 2²⁴ = 1312224482917 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312241260096 and 1312241260105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312241260153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656120630066 + 656120630067.

It is an arithmetic number, because the mean of its divisors is an integer number (656120630067).

Almost surely, 2^{1312241260133} is an apocalyptic number.

It is an amenable number.

1312241260133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312241260133 is an equidigital number, since it uses as much as digits as its factorization.

1312241260133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1312241260133 its reverse (3310621422131), we get a palindrome (4622862682264).

The spelling of 1312241260133 in words is "one trillion, three hundred twelve billion, two hundred forty-one million, two hundred sixty thousand, one hundred thirty-three".